C Program to Check Neon Number

C program to check neon number; Through this tutorial, we will learn how to check neon number in c program using for loop, while loop and function.

Let’s use the following algorithm to write a program to check whether a number is neon or not; as follows:

• Take the number as input from the user
• Find the square of the number
• Find the sum of the digits in the square
• Compare the sum with the number. If both are equal then it is a Neon number

Programs to Check Neon Number

• C Program to Check Neon Number using For Loop
• C Program to Check Neon Number using While Loop
• C Program to Check Neon Number using Function

C Program to Check Neon Number using For Loop

#include <stdio.h>

int main()
{
    int i, num, square, sumDigits = 0;

    printf("Enter a number: ");
    scanf("%d", &num);

    square = num * num;

    for(i = 0; i<=square; i++)
    {
        sumDigits += square % 10;
        square /= 10;
    }

    if (num == sumDigits)
    {
        printf("It is a Neon number\n");
    }
    else
    {
        printf("It is not a Neon number\n");
    }

    return 0;
}

The output of the above c program; as follows:

Enter a number: 10
It is not a Neon number

C Program to Check Neon Number using While Loop

#include <stdio.h>

int main()
{
    int num, square, sumDigits = 0;

    printf("Enter a number: ");
    scanf("%d", &num);

    square = num * num;

    while (square != 0)
    {
        sumDigits += square % 10;
        square /= 10;
    }

    if (num == sumDigits)
    {
        printf("It is a Neon number\n");
    }
    else
    {
        printf("It is not a Neon number\n");
    }

    return 0;
}

The output of the above c program; as follows:

Enter a number: 9
It is a Neon number

C Program to Check Neon Number using Function

#include <stdio.h>

int isNeon(int num)
{
    int square, sumDigits = 0;
    square = num * num;

    while (square != 0)
    {
        sumDigits += square % 10;
        square /= 10;
    }

    if (num == sumDigits)
    {
        printf("It is a Neon number\n");
    }
    else
    {
        printf("It is not a Neon number\n");
    }
}

int main()
{
    int n;

    printf("Enter a number: ");
    scanf("%d", &n);
    
    isNeon(n);


    return 0;
}

The output of the above c program; as follows:

Enter a number: 1
It is a Neon number

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